A rule for creating a pattern is given below.
Rule: Multiply x by 0.5 point, to get y
Which ordered pair, (x,y)), works for the rule?
Answers
Step-by-step explanation:
Q.1 Read the following passage and answer the questions that follow. Two and half hours later, they found themselves at a tiny, dusty railway station. They got down and stepped outside. A large well built men wearing a white dhoti and kurta and sporting a hug turban greeted them with folded hands. He led them to a bullock cart and much to Ajit's delight lifted and placed him on the cart. The cart trundled on for almost an hour till they finally reached the village. They alighted in front of a large brick house. An elderly man and a woman come out greeting Nanaji and fussing over the kids. They spoke in a dialect which Naina and Ajit found difficult to understand. Question- a) Describe the man who greeted by them at the station. He was _______________________ He was wearing ________________ He ______________________ head He _____________________ hands. b) find the meaning of the worlds from the dictionary and a sentence of your own for each of them. trundled; dialect; alighted:
Answer:
(10,5)
Step-by-step explanation:
We can turn the rule into an equation:
Rule: \maroonD{\text{Multiply by }0.5}Multiply by 0.5start color #ca337c, start text, M, u, l, t, i, p, l, y, space, b, y, space, end text, 0, point, 5, end color #ca337c to \blueD xxstart color #11accd, x, end color #11accd to get \goldD yystart color #e07d10, y, end color #e07d10.
\blueD x \maroonD{\times0.5} = \goldD yx×0.5=ystart color #11accd, x, end color #11accd, start color #ca337c, times, 0, point, 5, end color #ca337c, equals, start color #e07d10, y, end color #e07d10
Hint #22 / 5
We can substitute each ordered pair for \blueD{x}xstart color #11accd, x, end color #11accd and \goldD{y}ystart color #e07d10, y, end color #e07d10 to see if they work for the rule.
Ordered pair (\blueD{1}, \goldD 5)(1,5)left parenthesis, start color #11accd, 1, end color #11accd, comma, start color #e07d10, 5, end color #e07d10, right parenthesis
\begin{aligned} \blueD{1} \maroonD{\times0.5} &\stackrel{?}{=} \goldD{5}\\ 0.5 &\neq 5\end{aligned}
1×0.5
0.5
=
?
5
=5
Hint #33 / 5
Ordered pair (\blueD5, \goldD {10})(5,10)left parenthesis, start color #11accd, 5, end color #11accd, comma, start color #e07d10, 10, end color #e07d10, right parenthesis
\begin{aligned} \blueD{5} \maroonD{\times0.5} &\stackrel{?}{=} \goldD{10}\\ 2.5 &\neq 10\end{aligned}
5×0.5
2.5
=
?
10
=10
Hint #44 / 5
Ordered pair (\blueD{10}, \goldD {5})(10,5)left parenthesis, start color #11accd, 10, end color #11accd, comma, start color #e07d10, 5, end color #e07d10, right parenthesis
\begin{aligned} \blueD{10} \maroonD{\times0.5} &\stackrel{?}{=} \goldD5\\ 5 &\stackrel\checkmark= 5\end{aligned}
10×0.5
5
=
?
5
=
✓
5
Hint #55 / 5
The ordered pair that works for the rule is (10, 5)(10,5)left parenthesis, 10, comma, 5, right parenthesis.