Question

A runner accelerates from rest with an acceleration of 4 m/second2 for 2.3s. What will her speed be at the end of this time ​

Answer 1

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Answer 2

◇$\huge\underline\mathtt\red{GiveN:}$

• Acceleration(a)= 4 m/s²
• Time(t) =2.3 s
• Initial velocity(u) =0 m/s

Formula used:

$\huge{\underline{\boxed{a = \frac{v - u}{t} }}}$

◇$\huge\underline\mathtt\red{To~FinD:}$

A runner accelerates from rest with an acceleration of 4 m/second2 for 2.3s. What will her speed be at the end of this time?

$\rule{300}{2}$

Now,by putting the values in Newton's first law of motion, we get,

$\sf{a = \frac{v - u}{t}}$

$\sf{\implies 4 = \frac{v -0 }{2.3}}$

$\sf{\implies 4 = \frac{10v}{23}}$

$\sf{\implies 10v= 92}$

$\sf{\implies v = \cancel\frac{92}{10}}$

$\sf{\implies v =9.2 m/s}$

Her speed will be 9.2 m/s at the end of the time.

$\rule{300}{2}$

$\huge\underline\mathtt\red{Thank~You}$