Question

A runner completes a circular track of diameter 200m in 20seconds.The distance and magnitude of displacement in 1 minute 10 sec.What will be the distance travelled bythe runner?Pls answer with full steps..

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Answer 1

diameter =200m
radious =100m
circumference of circular track =2×22×100/7=4400/7m
1m 10secs=70see
runner completes in 20 seconds 4400/7m
in 1 second runner completes 4400/(7×20)
=220/7m

in 1min10sec =70sec completes 220×70/7
=2200m =2.2km
required distance travelled by runner =2.2km







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Answer 2

Hey, Here is your answer
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Diameter of circular track
= 200 m

Time taken by runner to complete one round
= 20 sec.

Total distance cover in one round
$= 2\pi \: r \\ \\ = 2 \times \frac{22}{7} \times \frac{200}{2} \\ \\ = \frac{4400}{7} \: \: m$
Total distance cover in 1 second
$= \frac{4400}{7} \times \frac{1}{20} \: \: m \\ \\ = \frac{220}{7} \: \: m$
Total distance cover in 1 min. 10 sec.
( = 60 + 10 sec. = 70 sec. ) is
$= \frac{220}{7} \times 70 \: \: m \\ \\ = 220 \times 10 \: \: m \\ \\ = 2200 \: \: m$
Now ,
Total displacement in 1 round = 0 m
and time taken to complete 1 round = 20 sec

:. In 20 sec. time the net displacement is 0 m

then ,
Total displacement in 60 sec. is
= 3 × 20 sec ..... ( as 20 sec. = 0 m )
= 3 × 0 m
= 0 m

Total displacement in 10 sec
$= 2r \\ = d \\ = 200 \: \: m$
:. Total displacement in 70 sec.
= 60 + 10 sec. .... ( as displacement in 60 sec. = 0 m and 10 sec. = 200 m )
= 0 + 200 m
= 200 m

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