A runner completes one round of a circular path of radius r in 40 second . His displacement after 2 minutes 20 seconds will be
Answers
Answered by
96
In 40 secs-->1 round..
In 2 mins 20 secs=140 secs
No. Of rounds=140/40=3½
Therefore the runner would reach the diametrically opposite point..
=> displacement = diameter
=2r
In 2 mins 20 secs=140 secs
No. Of rounds=140/40=3½
Therefore the runner would reach the diametrically opposite point..
=> displacement = diameter
=2r
Answered by
62
Answer:
His displacement after 2 minutes 20 seconds will be 2 r.
Explanation:
Given that,
Radius of the circle = r
We need to calculate the displacement,
A runner completes one round of a circular path of radius r in 40 second.
A runner completes 3.5 round in 140 second.
So, the displacement will be zero in 3 round.
In 0.5 round, the runner covers the distance is 2 r.
Therefore, The displacement will be
Displacement = final position - initial position
Hence, His displacement after 2 minutes 20 seconds will be 2 r.
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