Question

A runner is initially going 5 m/s to the right when she slows down at to 2 m/s over 10 seconds.
a) What is her acceleration?
b) How far does she travel in these 10 seconds?

Answer 1

Explanation:

given that,

u = 5m/s

v= 2m/s

t = 10sec

accn = v - u/t

= 2m/s - 5m/s/10sec

= -3m/s/10sec

= -0.3m/s^2

distance = ut + 1/2 × at^2

= 5m/s + 1/2 × (-0.3m/s^2) × 10^2sec

= 5m/s + 1/2 × (-0.3m/s^2) × 100sec

= 5m/s + 1/2 ×(-30m/s)

= 5m/s + (-15m/s)

= 5m/s - 15m/s

= -10m ans

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