Question

A runner’s initial velocity is 2m/s, and he reached final velocity 10 m/s in 8 seconds.
Then he slows down to a final velocity of 4 m/s in 6 seconds. Calculate his
acceleration during the first 8 seconds and during the last 6 seconds.

Answer 1

Answer:

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Explanation:

Answer 2

Answer:

$\huge \underbrace \mathfrak \red{Solution࿐꧂}$

$\large \overbrace \underbrace \mathfrak \red{Part→I࿐꧂}$

$</p><p>\blue{acceleration = \frac{(final \: velocity - initial \: velocity}{time \: taken} }$

$\huge \underbrace \mathfrak \red{Solution࿐꧂}$

$\large \overbrace \underbrace \mathfrak \red{Part→I࿐꧂}$

$</p><p>\blue{acceleration = \frac{(final \: velocity - initial \: velocity}{time \: taken} }$

$\blue{ \frac{10 - 2}{8} }$

$\blue {\frac{8}{8} }$

$\blue{1}$

$\large \overbrace \underbrace \mathfrak \red{Part→II ࿐꧂}$

$\blue{acceleration = \frac{(final \: velocity - initial \: velocity}{time \: taken} }.$

$\blue{ \frac{6- 10}{8} }$

$\blue{ \frac{-4}{8} }$

$\blue{\frac{-1}{2}}$blue{ \frac{10 - 2}{8} }[/tex]

$\blue {\frac{8}{8} }$

$\blue{1}$

$\large \overbrace \underbrace \mathfrak \red{Part→II ࿐꧂}$

$\blue{acceleration = \frac{(final \: velocity - initial \: velocity}{time \: taken} }.$

$\blue{ \frac{6- 10}{8} }$

$\blue{ \frac{-4}{8} }$

$\blue{\frac{-1}{2}}$