A running car has a uniform acceleration of 4 m/s². What distance will it cover in 10 second after the start?
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Given -
a = 4m/s² , t = 10s , u = 0 (initially it was at rest)
but, acc. to third eq. of motion --
S = ut +1/2at²
Therefore,
distance traveled(S) = 0×10 + (1/2×4×10×10)
S = 0+200 = 200 meters.
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a = 4m/s² , t = 10s , u = 0 (initially it was at rest)
but, acc. to third eq. of motion --
S = ut +1/2at²
Therefore,
distance traveled(S) = 0×10 + (1/2×4×10×10)
S = 0+200 = 200 meters.
If you are satisfied with this answer plz mark this as brainliest
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