Question

a running man has half the kinetic energy of that of a boy of half of his mass. the man speed up by 1 m/s so as to havesame kinetic energy as that of the boy. the original speed of the ma will be...(a)= √2m/s (b)={√2-1}m/s (c)= 1/√2-1m/s (d)= 1/√2m/s​

Answer 1

Explanation:

the answer is in image. Hope it helps.