Question

A's age is 2/5 of B's age 6 year from now B's age will be one year less than double of A's age at that time. What is A's present age​

Answer 1

Answer:

10 years

Step-by-step explanation:

☆To find:

▪︎A's present age

☆Given :

▪︎A's age is 2/5 of B's age

▪︎6 year from now B's age will be 1 year less than double of A's age

☆Assuming:

▪︎Let B's age be x

▪︎Therefore, A's age=2/5x=2x/5

☆Solution:

▪︎6 years hence age of B = x+6

▪︎6 years hence age of A= 2x/5+6

ATQ

$2( \frac{2x}{5} + 6) - 1=x + 6 \\ = > 2( \frac{2x + 30}{5} ) - 1 = x + 6 \\ = > \frac{4x + 60}{5} - 1 = x + 6 \\ = > \frac{4x + 60 - 5}{5} = x + 6 \\ = > 4x + 55 = 5(x + 6) \\ = > 4x + 55 = 5x + 30 \\ = > 4x - 5x = 30 - 55 \\ = > - x = - 25 \\ = > x = 25$

▪︎Therefore,Age of B= 25 years

▪︎Therefore, age of A

$= \frac{2}{5} \times 25 = 10 \: years$

☆Hence:

▪︎Present age of A=10 years

☆Verification:

▪︎6 years hence age of B= 25+6=31

▪︎6 years hence age of A= 10+6=16

▪︎31 years= (16×2)-1

Hence,verified

Hope it helps....

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