Question

a's age is 4 times that of b's age. 10 years ago, a's age was 19 times that of b's age.find the present ages of a and b.(linear equation in one variable)​

Answer 1

THE ANSWER IS IN THE PICTURE.

.

.

.

HOPE THE ANSWER HELPED YOU.

IF POSSBLE OR THE ANSWER HELPED YOU PLEASE MARK ME AS BRAINLIEST .

THANKS!!!

Answer 2

$\huge\mathtt\red{Answer}$

⇝ Given :-

a's age is 4 times that of b's age.

10 years ago, a's age was 19 times that of b's age.

⇝ To Find :-

Their Present Ages

⇝ Solution :-

Let,

Present Age of a = 4x years

Accordingly ,

Present Age of b = x years

❒ 10 Years Ago :

Age of a = (4x - 10) years

Age of b = (x - 10) years

✏ According To Question :

4x−10=19(x−10)

:⟼4x−10=19x−190

:⟼4x−19x=−190+10

−15x= −180

X=

$\frac{ - 180}{ -15 }$

$x= 12$

As,

Present Age of a = 4x years

Present Age of b = x years

$Hence,</p><p></p><p>\begin{gathered} \pink{\begin{cases} \bf Present \: \: Age \: of \: a = 48 \:years \\ \\ \bf Present \: Age \: of \: b = 12 \: years\end{cases}}\end{gathered}⎩⎪⎪⎨⎪⎪⎧PresentAgeofa=48yearsPresentAgeofb=12years</p><p>$

i hope it will help you Ankit ✌️