A's age is 4 times that of B's age.10 years ago,A's age was 19 times that of B's age.Find the present age of A and B.
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let the age of A be x and B be y
x=4y
(x-10) = 19(y-10)
x-10=19y-190
x-19y=-180
4y-19y=-180
-15y=-180
y=12
age of B is 12 yrs
age of A is 48 yrs
x=4y
(x-10) = 19(y-10)
x-10=19y-190
x-19y=-180
4y-19y=-180
-15y=-180
y=12
age of B is 12 yrs
age of A is 48 yrs
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