A's age is 6 time of B's age after 5 years A's will be 3 time as old as B's find their age
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Hi ,
At present,
_________
let the age B age = x years
age of the A = 6 times of B's age
= 6x years
After 5 years
__________
age of B = ( x + 5 ) years
age of A = ( 6x + 5 ) years
given,
age of A = 3 times of B's age
6x + 5 = 3 ( x + 5 )
6x + 5 = 3x + 15
6x - 3x = 15 - 5
3x = 10
x = 10/3
Therefore,
at present
age of B = x = 10/3 years
age of A = 6x = 6 × 10/3 = 20 years
i hope this will useful to you.
*****
At present,
_________
let the age B age = x years
age of the A = 6 times of B's age
= 6x years
After 5 years
__________
age of B = ( x + 5 ) years
age of A = ( 6x + 5 ) years
given,
age of A = 3 times of B's age
6x + 5 = 3 ( x + 5 )
6x + 5 = 3x + 15
6x - 3x = 15 - 5
3x = 10
x = 10/3
Therefore,
at present
age of B = x = 10/3 years
age of A = 6x = 6 × 10/3 = 20 years
i hope this will useful to you.
*****
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