Question

A's age is five times as that of B. Ten years later, A's age will be thrice that of B, find A's age. ​

Answer 1

Answer:

Step-by-step explanation:

Present age

A=5*B     (equation 1)

10 years later

A age will be=A+10

B age will be=B+10

Equation 2:

(A+10)=3(B+10)

Substituting value of A from equation 1:

5B+10=3B+30

5B-3B=30-10

2B=20

B=10

From equation 1=

A=5*B

A=5*10=50

Answer 2

Answer:

60 years

Step-by-step explanation:

Let the present age of B =x

and A age=5x

After ten years B age=x+10

A age=5x+10

A/Q....

3(x+10)=5x+10

3x+30=5x+10

3x-5x=10-30

-2x=-20

x=10

A age=5×10+10

60 years

I hope this is helpful for you!