Question

A’s age is thrice that of B’s and four times that of C’s. Find A:B:C.​

Answer 1

Question :--- A’s age is thrice that of B’s and four times that of C’s. Find A:B:C. ?

Solution :---

Given that, A = 3B = 4C

Let A = 3B = 4C = k . ( where k is any constant term. )

So ,

→ A = k

→ 3B = k

→ B = (k/3)

→ 4C = k

→ C = (k/4) .

So,

→ A : B : C = k : k/3 : k/4

→ k : k/3 : k/4

Taking LCM of Denominator now,

→ ( 12k : 4k : 3k )/12

→ 12 : 4 : 3 .

Hence, A : B : C = 12 : 4 : 3 .