Question

A's age is twice B's 4year ago A wa
s three times as old as B find the age​

Answer 1

Step-by-step explanation:

Let the age of B 4 years ago be X years.

Therefore,age of A will be 4X

After 4 years(Present time)

Age of B will be (X+4) years

And, age of A will be (4X+4)years

A/q=>3(X+4)=(4x+4)

3X+12=4X+4

3x-4x=4-12

-X= -8

X=8

Therefore, Present age of B= X+4= 12 Years

And Age of A= 3(X+4)= 36 years