A(s) +B(8) +heat F 2Cs) +2D(8)
At equilibrium the pressure of 'B' is doubled.
By what factor the concentration of 'D'
should change to reattain the equilibrium
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Answer:
A(s) + B(8) = 2C(s) + 2D(8)
t=0 2a a 0 0
t=t 2a-x a-x x x
ar equilibrium the pressure of B is doubled
a-x=2x
a=3x
x=a/3
at t=t 3a/2 a/2 a/2 a/2
K=[A] [B]/[2C][2D]
K=[3a/2][a/3]/[a/3]^2
K=3
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