Question

A's capacity is half the capacity of B and C together. The capacity of A and C together is 19/8 times of the capacity of B alone.The ratio of the capacity B and C is 4:5.If together they finish the work in 13 1/3 days .Find out in how many days they can finish the work individually.

Answer 1

Capacity of B and C = 4:5 = 4x:5x
Capacity of A = 1/2 Capacity of B and C = 1/2(4+5) = 9/2 x

A,B,C together completes the work in 13 1/3 days = 40/3 days.

Total work = Days * Total efficiency 
                 = 40/3 * (4x+5x+9x/2) = 40/3 * 27x/2 = 180x.

A :
Efficiency * Days = Total work
9x/2 * Days = 180x
Days = 40.
B:
4x * Days = 180x
Days = 45
C:
5x*Days = 180x
Days = 36
Hence A can finish the work alone in 40 days, B in 45 days, C in 36 days.
Hope it helps

Answer 2

here is your ans, but i guess, here capacity is the capacity of capacitor.