A's efficiency is 20% more than B. If A and B together can
do a job in 60 days, what is the time taken by B?
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Answer:
the time taken by B is 132 Days
Step-by-step explanation:
A's efficiency is 20% more than B
A =20% B
Assume that
A=100%
So,
B=120%
A:B=100:120
A:B=10:12
A:B=5x:6x
A/B=5/6
A=1/5x
B=1/6x
A+B=1/60days
1/5x+1/6x=1/60 days
5x+6x/30x²=1/60days
11x/30x²=1/60 days
11/30x=1/60 days
11=30x/60
11=x/2
x=22
A=5x
A=5(22)=110 Days
B= 6(22)=132 Days
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