Question

A's father is twice as old as A.twenty years ago A's father was 6 times as old as A.what is the present age of A?
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Answer 1

Answer:

Let the present age of the son be x. Let the present age of the father be 2x.

When you say 6 times his son’s age, I’m assuming it means his son’s age 20 years ago.

The age of the son 20 years ago is x-20 and the age of the father is 2x-20.

So, 2x-20=6(x-20)

Solving this linear equation, we get 4x=100 or x=25.

Hence, the present age of the son is 25 years while the age of the father is 50 years.

You can check this. 20 years ago, age of the son was 5 years while age of the father was 30 years. 30 is 6 times 5. Hence, the answer obtained is correct!

Hpoe this helps...

Answer 2

Answer:

Let the age of son be x years and father be 2x years.

20 years back, their ages were x−20 and 2x−20

As per the given condition, we get

2x−20=6(x−20)

⇒2x−20=6x−120

⇒2x−6x=20−120

⇒−4x=−100

⇒x = 100/4

⇒x=25

∴ son's age is 25 years and father's age is (2×25)=50 years.