Question

A s height is more than B's height by 20% by what percent is B's height less than A's height

Answer 1

let B's height be X.

Then,

A's Height = X + 20X/100=X + X/5=6X/5

A's height = 6X/5

$percentge \: = \: (\frac{ \frac{6x}{5} - x}{ \frac{6x}{5} } \times 100)$

$percentage = 100 \div 6 \: = 16.667\%$

So, your Answer is 16.667 %

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