Math, asked by redrabbit, 2 months ago

A's income is 10 % less than B's income.. How much percentage is B's income more than A's income...

please tell mee step by step please..​

Answers

Answered by june78
2

Step-by-step explanation:

Answer:

11.11%

Step-by-step explanation:

Let the income of B be 100

We are given that A's income is 10% less than B's income.

So, A's income = 100-\frac{10}{100}{ \times 100 = 90

Difference in income = 100-90 = 10

Now we are supposed to find How much % is B's income more than A's income

So,percentage = \frac{10}{90} \times 100 =11.11 \%

90

10

×100=11.11%

Hence B's income is 11.11% more than A's income

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