Question

A's income is 20% less than of B. By what percent is B's income more than A's??

Answer 1

A = $\frac{80}{100}$ B

B = $\frac{100}{80}$ A

B = $\frac{5}{4}$ A

B = $(1+\frac{1}{4} )$ A

Therefore B's income is $\frac{1}{4}$ ( 25%) times more than that of A's income.

Answer 2

Let the income of B is 100 Rs . Then income of A is 80 Rs. As income of A is 20% less than B . So % by which Income of B is more than A is $\frac{B-A}{A} *100%$ = 25%