Math, asked by ritua8385, 2 months ago

A's income is 20% less than that of b by what percent is B's income more than A's​

Answers

Answered by sahu34909
2

Answer:

B’s income is 25% more than A.

Step-by-step explanation:

A’s income = (100-20)% of B

A’s income = (100-20)% of BA’s income = (80/100)*X

A’s income = 0.80x

A’s income = 0.80xPercentage increase in amount of B

A’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100

A’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100

A’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100

A’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100=0.25*100

A’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100=0.25*100=25

Therefore, B’s income is 25% more than A.

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Answered by ghodvindekalapana
0

Answer:

this is the correct answer

Step-by-step explanation:

hope you like that ☺️

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