Math, asked by Rumaisa3101, 1 year ago

A's is five times as that of B. ten years later, A,s will be thrice that of B, find A's age

Answers

Answered by palkin
15

Answer:

A's age is 50 years.

Step-by-step explanation:

Let the age of B be x

Therefore, according to the situation given in the question,

Age of A will be 5x,

A.T.Q.

3(10 + x) = 10 +5x

30+3x = 10+5x

30 - 10 = 5x - 3x

20 = 2x

x = 10

So, age of B is 10 years

and,

Age of A is 5×10 =50 years.

Answered by Anonymous
24

Answer:

Solution : Present age of B = x years

Present age of A = 5x years

According to question

5x + 10 =3(X+ 10)

5x + 10 = 3x + 30

5x – 3x = 30 – 10

2x = 20

X = 20/2

X = 10

Hence present age of B = 10 years

And present age of A =5x10 = 50 years

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