A's mother is four times as old as A. After five years, her mother will be three times as old as she will be then. What are their present ages?
PLEASE USE LINEAR EQUATION BASED ON ONE VARIABLE
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Solution
Given:-
- A's mother is four times as old as A
- After five years, her mother will be three times as old as she will be then.
Find :-
- Thier present ages
Explanation
Let,
- Age of A's mother = x years
- Age of A = y years
According to question,
Case 1.
==> x = 4y
==> x - 4y = 0__________(1)
Case 2.
==> (x + 5) = 3×(y + 5)
==> x - 3y = 15 - 5
==> x - 3y = 10_________(2)
Sub. equ(1) & equ(2)
==> -4y + 3y = -10
==> -y = -10
==> y = 10
Keep in equ(1)
==> x - 4 × 10 = 0
==> x = 40
Hence
- Present age age of A's Mother = 40 years
- Present age of A = 10 years
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