Math, asked by tkinley68, 7 months ago

A’s mother was four times as old as A ten years ago. After 10 yrears she will be twice as old as A. then A’s present age is 30 years 20 years 24 years 25 years

Answers

Answered by madhukumariswn88
1

Let A’s present age be x.

Thus A’s mother's age 10 years ago was 4 (x - 10)

A’s mother's age after 10 years will be 2 (x + 10)

As per statement, A's mother was 4 times as old as A ten years ago. After ten years, she will be twice as old as A. Accordingly

2 (x + 10) - 4 (x - 10) = 20

2x + 20 - 4x + 40 = 20

2x - 4x + 60 = 20

—2x = 20 — 60

—2x = —40

x = 40/2

x = 20

Thus A’s present age is 20 years.

Answer A’s present age is 20 years.

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