Math, asked by Arya3321, 2 days ago

A's present age is to B's present age is 7:9. twelve years ago, their ages were in ratio 3:5 when would the ratio of their ages be 6:7​

Answers

Answered by Ace0615
1

Given:

A's present age is to B's present age is 7:9.

Let A's and B's present age be 7x and 9x respectively.

Twelve years ago, their ages were in ratio 3:5.

Let A's and B's age before 12yrs be (7x - 12) and (9x - 12) respectively.

Solution:

ATQ.

(7x - 12) / (9x - 12) = 3 / 5

=⟩ 5(7x - 12) = 3(9x - 12)

=⟩ 35x - 60 = 27x - 36

=⟩ 35x - 27x = 60 - 36

=⟩ 8x = 24

=⟩ x = 24 / 8

= 3

Therefore; A's present age = 7x

= 7 × 3 = 21yrs

B's present age = 9x

= 9 × 3 = 27yrs

Now,

Let after y yrs be the ratio of A's to B's ages be 6:7

Therefore, ATQ.

(21 + y) / (27 + y) = 6 / 7

=⟩ 7(21 + y) = 6(27 + y)

=⟩ 147 + 7y = 162 + 6y

=⟩ 7y - 6y = 162 - 147

=⟩ y = 15yrs

Hence, after 15 yrs, the ratio of the ages of A and B would be 6:7.

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