Question

A s salary is 20% more than of B .what percentage is B s income less than that of A

Answer 1

According to question:

A is 20% more than B

Let B=100

Then A=120

According to question how much is B less than A

A=120 B=100 different=20

{(120–100)/120}*100

={20/120}*100

={1/6}*100

=100/6

=16.67%

Finally you answer= 16.67%, B less than A

Answer 2

Here's your answer..

Solution:-

Let the B 's income be 100

So,
A 's Income is 100+20
=>₹120

Difference in their Income is :-
A 's - B 's
=>120-100
=>20

Now,
Percentage Less of B 's Income than A 's is:-
$= > \frac{20}{120} \times 100 \\ = > 16\frac{4}{6}$

OR

=>16.67
Hope it helps you....