A sailing boat with triangular masts is shown below. Two right triangles can be observed. Triangles ABC and ABD, both right-angled at B. The distance BC = 1 m and BD = 2 m and height AB = 4 m. B The value of sec D is: O a) 1/15 O b) V5/2 O c) V5 d) 2/15
Answers
Given: Triangles ABC and ABD, both right-angled at B. The distance BC = 1 m and BD = 2 m and height AB = 4 m
To Find : The value of sec D
Solution:
tan α = Perpendicular / Base
tan D = AB/BD
=> tan D = 4/2
=> tan D = 2
Sec²D = 1 + tan²D
=> Sec²D = 1 + 2²
=> Sec²D = 1 + 4
=> Sec²D = 5
=> Sec D = √5
Hence Value of sec D is: √5
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Answer:
√5
Step-by-step explanation:
tan α = Perpendicular / Base
tan D = AB/BD
⇒ tan D = 4/2
⇒ tan D = 2
Sec²D = 1 + tan²D
⇒ Sec²D = 1 + 2²
⇒ Sec²D = 1 + 4
⇒ Sec²D = 5
⇒ Sec D = √5
∴ Value of sec D is: √5
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