Question

A sailing boat with triangular masts is shown below. Two right triangles can be observed. Triangles ABC and ABD, both right-angled at B. The distance BC = 1 m and BD = 2 m and height AB = 4 m. B The value of sec D is: O a) 1/15 O b) V5/2 O c) V5 d) 2/15​

Answer 1

Given: Triangles ABC and ABD, both right-angled at B. The distance BC = 1 m and BD = 2 m and height AB = 4 m

To Find : The value of sec D

Solution:

tan α = Perpendicular / Base

tan D  = AB/BD

=> tan D = 4/2

=> tan D = 2

Sec²D = 1 + tan²D

=> Sec²D = 1 + 2²

=> Sec²D = 1 + 4

=> Sec²D = 5

=> Sec D = √5

Hence Value of sec D is: √5

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