Math, asked by nirmalkadiaa67, 8 months ago

a sailor goes 10 km downstream in 1 hr and return in 1 hr 40 min find the speed of the sailor in still water and speed of the current​

Answers

Answered by Anonymous
1

Answer: If it's correct then plzzz mark me as the Brainliest

Step-by-step explanation: Let the speed of boat in still water=x km/hr

The speed of current=y km/hr

speed  of  boat  downstream=x+y

∵speed=  

time

distance

​  

 

⇒speed=  

3

2

​  

 

8

​  

     [∵40min=  

60

40

​  

hrs=  

3

2

​  

]

⇒x+y=  

2

8×3

​  

 

⇒x+y=12....(1)

speed  of  boat  upstream=x−y

⇒speed=  

1

8

​  

⇒x−y=8....(2)

Add (1) and (2)

⇒2x=20⇒x=10

put x=10 in (1)

⇒10−y=8⇒y=2

Hence, the speed of boat in still water=10km/hr

The speed of current=2km/hr

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