a sailor goes 10 km downstream in 1 hr and return in 1 hr 40 min find the speed of the sailor in still water and speed of the current
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Answer: If it's correct then plzzz mark me as the Brainliest
Step-by-step explanation: Let the speed of boat in still water=x km/hr
The speed of current=y km/hr
speed of boat downstream=x+y
∵speed=
time
distance
⇒speed=
3
2
8
[∵40min=
60
40
hrs=
3
2
]
⇒x+y=
2
8×3
⇒x+y=12....(1)
speed of boat upstream=x−y
⇒speed=
1
8
⇒x−y=8....(2)
Add (1) and (2)
⇒2x=20⇒x=10
put x=10 in (1)
⇒10−y=8⇒y=2
Hence, the speed of boat in still water=10km/hr
The speed of current=2km/hr
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