Question

A salesman has a 38% chance of sale at his first stop, a 44% chance of sale at his second stop, and a 28% chance of sale at both stops. Find the odds that he will make a sale at the second stop.

Answer 1

Answer:

The chance for the percent sale at the second stop is:

P2=44% .

The expression for the odds that salesman make a sale at the second stop is,

x =P2/1−P2

Substitute the values.

x = 0.44/1−0.44

=11/14

Thus, the odd is from 11 to 14 that salesman make a sale at the second stop.