Question

A salesman has a 60% chance of making a sale to each customer the behaviour of successive customers is independent. If two customers A and B enter, what is the probability that the sales man will make a sale to A or B ? Chp-probability , plz, plz answer

Answer 1

Hey beautiful

Here is you solution

P(sale)= 0.6

P(not sale)= 0.4

P(sale A or B) = P(Sale A)+P(sale B) - P(sale A and B)

= 0.6+0.6 -0.6(0.6) = 1.2-0.36 = 0.84

Answer: 0.84

Answer 2

Given: A salesman has a 60% chance of making a sale to each customer the behaviour of successive customers is independent.

To find: If two customers A and B enter, the probability that the salesman will make a sale to A or B.

Solution:

According to the question, the probability that a salesman makes a sale to a customer is 60%. This can be written as follows.

$\frac{60}{100} = \frac{6}{10}$

Hence, the probability that the salesman makes a sale to A is 6/10 and the probability that the salesman makes a sale to B is also 6/10. But the probability that he will make a sale to A or B is

$P(A or B) = \frac{6}{10} +\frac{6}{10}$

               $= \frac{12}{10}$

               $= \frac{6}{5}$

Therefore, the probability that the salesman will make a sale to A or B is 6/5.