Math, asked by shreyasvinc, 11 months ago

A salesman mixed two kinds of candies worth $1.25 and $1.6 a pound, respectively. He made a mixture of 70 pounds to sell at $1.4 a pound. How many pounds of each did he use?

Answers

Answered by ayeshabani17
1

Answer:

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Answered by eudora
5

40 pounds of type(1) and 30 pounds of type (2) candies were mixed.

Step-by-step explanation:

Let the salesman mixed mixed candies x pounds of type (1) and y pounds of type (2) candies.

By adding x and y pounds of candies mixture become 70 pounds.

x + y = 70 -------(1)

He adds x pounds of type (1) candies costing $1.25 and type (2) candies costing $1.6 to make the mixture of 70 pounds costing $1.4.

Therefore, the equation will be

1.25x + 1.6y = 70×1.40

1.25x + 1.6y = 98

By dividing this equation by 1.25

x + 1.28y = 78.4 -----(2)

By subtracting equation (1) from (2)

(x + 1.28y) - (x + y) = 78.4 - 70

1.28y - y = 8.4

0.28y = 8.4

y = \frac{8.4}{0.28}

y = 30 pounds

from equation (1),

x + 30 = 70

x = 70 - 30

x = 40 pounds

Therefore, 40 pounds of type(1) and 30 pounds of type (2) candies were mixed.

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