A saline contains 40g of (nacl) common salt and 320g of water .Calculate the number of moles of common salt in the solution
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Answered by
6
given mass of NaCl=40g
molar mass of NaCl=58.5g mol
number of moles =given mass/ molar mass
n=40/58.5=0.683 moles
(answer)
Answered by
2
Gram molecular mass of NaCl = (23+35.5)
= 58.5
Hence, moles present in 40g of NaCl
= 40/58.5
= 0.6837 (approximate)
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