Chemistry, asked by vyshu5475, 11 months ago

A saline solution contain 40g of sodium chloride and 320 g of water. Calculate the number lf miles of common salt present in the solution and the number of molecules of watet present in the solutilm answer based on chaptet atoms and molecules of myguide

Answers

Answered by Agastya0606
0

The number of moles of common salt present in the given solution can be calculated using the formula: No. of moles = Given weight/Molar mass

Given weight of sodium chloride = 40 g

Molar mass = 23 + 35.5 = 58.5 g

Therefore, number of moles = 40/58.5 = 0.6837 moles

Number of molecules of water present in the solution = No. of moles of water * Avogadro number

No. of moles of water = 320/18 = 17.78 moles

Number of molecules = 17.78 * 6.022 * 10²³ =  1.07 * 10²⁵

Similar questions