Question

A salit
wooden toy
the shape of a cone
surmounted on a hemisphiere of the some radius
2 • 1 cm If the height the wooden toy is
8.1. cm .find the total surface area and volume
of the
toy​

Answer 1

Answer:

V = (4/3)πr³

So the volume of a hemisphere will be half of that, which is (2/3)πr³

The volume of a cone of base radius r and height h is:

V = (1/3)πr²h

We are told that r = 4.2 cm

The total height of the toy is made up of (the height of the cone) + (height of hemisphere)

So the height of the cone = 10.2 - 4.2 = 6 cm

So the volume of the toy = (volume of hemisphere + volume of cone)

= (2/3)π * 4.2³ + (1/3)π * 4.2² * 6

= 155.2 cm³ + 110.8 cm³

= 266 cm³

If this is not clear, Please refer the attachment ;)

Hope This Helps :)

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