Question

A salt 'X' reacts with conc. Sulphuric Acid to give a gas 'Y' which gives curdy white ppt 'A' when added to Silver Nitrate solution. When excess of ammonia solution is added to this ppt 'A', it turns to a colourless Solution 'B

Answer 1

Explanation:

Given -

1. A salt ‘X’ reacts with Conc. Sulphuric acid to give a gas Y.
2. X gives curdy white ppt. A when added to AgNO3
3. When Excess of NH3 is added to ppt. A, it turns into a colourless solution B.

To Find -

1. What is X ?
2. What's Y ?
3. What's white ppt. A ?
4. What's B ?

Now,

As we know that :-

• NaCl reacts with AgNO3 to form white ppt. AgCl.

1)

X is NaCl

2)

X + H2SO4 → Gas Y

It means,

2NaCl + H2SO4 → Na2SO4 + 2HCl

Hence,

Gas Y is HCl

3)

X + AgNO3 → white ppt. A

It means,

NaCl + AgNO3 → AgCl + NaNO3

Hence,

white ppt. A is AgCl

4)

White ppt. A + NH3(excess) → B

It means,

AgCl + NH3(excess) → [Ag(NH3)2]+ + Cl-

Hence,

Solution B is [Ag(NH3)2]+