Question

A samosa and a brownie cost rupees 16 . If the brownie cost rupees 5 more than the samosa what is the cost of 3 brownies and 2 samosa ?

Answer 1

Answer:

Let the cost of Brownie be Rs x and cost of samosa be Rs y

According to fist condition,

x+y=16--------(1)

According to second condition,

x= y+5-----(2)

Substitute equation 2 in equation 1

y+5+y=16

2y+5=16

2y=11

y=11/2= 5.5 rupees

Put y=5.5 i equation 1,

x+5.5=16

x=16-5.5=10.5 rupees

Cost of 3 brownies=3x= 3×5.5= 16.5 rupees

Cost of 2 samosas= 2x= 2×5.5= 11.0 rupees

Hope that helps!

Answer 2

Answer:

Step-by-step explanation:

let the cost of one brownie be x

let the cost of one samosa be y

according to the question :

one samosa + one brownie =16

x + y +16 ⇒ equation 1

cost of brownie = cost of samosa + 5

x = y+5 ⇒ equation 2

put eqn 2 in eqn 1

then : y + 5 + y =16

2y +5 =16

2y = 16 - 5

2y = 11

y = 11/2

y=5.5

so the cost of one samosa = 5.5 rs

substitute y value in eqn 1

x + 5.5 =16

x = 16 - 5.5

x = 10.5

so the cost one brownie = 10.5 rs

so the cost of 3 brownies and 2 samosa = 3x + 2y

3(10.5) + 2 (5.5)

31.5 + 11 = 42.5

so the cost of 3 brownies and 2 samosa is 42.5 rs

i hope u understood it !!