Question

A sample contains 200 atoms of hydrogen, 0.05 gm atom of nitrogen, 10 gm atom of oxygen.
What is the approximate no. of total atoms
(A) 200
(B) 6223
(C) 3×10^22
(D) none of these
​

Answer 1

Answer:

Explanation:

Number of Hydrogen atoms = 200

Gram atom of Nitrogen = 0.056 g

14 grams atom of nitrogen =  6.022 * 10 ²³ atoms of nitrogen

Therefore , 0.05 grams atom of nitrogen =( 6.022 * 10 ²³ / 14 )  * 0.05

                                                = 0.0215 * 10²³ atoms of nitrogen.

Oxygen = 10⁻²⁰ g

16 grams atom of oxygen =  6.022 * 10 ²³ atoms of oxygen

10⁻²⁰  grams of oxygen = ( 6.022 * 10 ²³ / 16 )  * 10⁻²⁰ = 376.38 atoms of oxygen.

Total number of atoms = No. of hydrogen atoms + gram atom of nitrogen + gram atom of oxygen

Total number of atoms = 200 + ( 0.0215 * 10²³ ) + 376.38

              

    Total number of atoms = 2.15 * 10²¹ atoms.

Hope it helps.

Answer 2

Answer:

Please refer the attachment dear.

HOPE IT HELPS YOU