A sample contains 200 atoms of hydrogen,0.05gm atom of nitrogen,10 raise to -20gm atom of oxygen.what is the approximate no. Of total atoms
Answers
Answer:
2.1507×10^21 atoms is the correct answer.
Explanation:
Given data :
Number of atoms of hydrogen = 200
No of atom of nitrogen = 0.05
Number of atom of oxygen = 10^-20
To find
The approximate number of total atoms
Solution:
We know that
14 grams of nitrogen will require 6.022×10²³ atoms
Therefore 0.05 grams of nitrogen will require x atoms
By cross multiplication,
x = 6.022×10²³ × 0.05/ 14
= 2.1507×10²¹ atoms of nitrogen
Therefore 0.05 grams of nitrogen will require 2.1507×10²¹ atoms
Now we know that,
16 grams of oxygen will require 6.022×10²³ atoms
Therefore 10^-20 grams of oxygen will require x atoms
By cross multiplication,
x = 6.022×10²³ × 10^-20/ 16
= 376.375 atoms
Therefore 10^-20 grams of oxygen will require 376.375atoms
Now total atoms of compund
= atoms of hydrogen+ atoms of nitrogen+ atoms of oxygen
= 200+ 2.1507×10²¹ + 376.375
= 2.1507*10^27 atoms
Hence, 2.1507×10^21 atoms is the correct answer.
Solution:
Number of Hydrogen atoms = 200
Gram atom of Nitrogen = 0.056 g
14 grams atom of nitrogen = 6.022 * 10 ²³ atoms of nitrogen
Therefore , 0.05 grams atom of nitrogen =( 6.022 * 10 ²³ / 14 ) * 0.05
= 0.0215 * 10²³ atoms of nitrogen.
Oxygen = 10⁻²⁰ g
16 grams atom of oxygen = 6.022 * 10 ²³ atoms of oxygen
10⁻²⁰ grams of oxygen = ( 6.022 * 10 ²³ / 16 ) * 10⁻²⁰ = 376.38 atoms of oxygen.
Total number of atoms = No. of hydrogen atoms + gram atom of nitrogen + gram atom of oxygen
Total number of atoms = 200 + ( 0.0215 * 10²³ ) + 376.38
Total number of atoms = 2.15 * 10²¹ atoms.