Question

A sample contains 3.01 x 1023 molecules of Sin and its mass is 54 g. What is the value of n?
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Answer 1

Explanation:

We know that

no.of molecules= mole(n) × N(Avogadro's no.)

given no.of molecules = 3.01 × 10^23

Avogadro no. = 6.02 × 10^23

$3.01 \times {10}^{23} = n \times 6.02 \times {10}^{23}$

$n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} }$

$n = \frac{1}{2}$

$n = 0.5$

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