Question

A sample of 0.00832 g an unknown gas has a volume of 250.0 mL. at a
pressure 38.3 mmHg and a temperature of 22 °C. The unknown Compound is:​

Answer 1

200 K

Initial mass W=5 g

Initial pressure =P

Initial temperature =T K

Final mass W=5−1 g

Final pressure =P

Final temperature =T+50 K

WT

P

=

WT

′

P

′

5g×TK

P

=

(5−1)g×(T+50)K

P

′

5×T

1

=

4×(T+50)

1

5×T=4×(T+50)

5T=4T+200

T=200 K

Thus, the original temperature was 200 K