Question

a sample of 0.177g of an ideal gas occupies 1000cm^3 at stp.calculate. calculate rms speed of the gas molecules.

Answer 1

answer is approximate.. hope it helps you...

Answer 2

The rms velocity of the gas molecule is 1310.32 m/s.

Explanation:

Given that,

Mass of ideal gas, m = 0.177 g = $1.77\times 10^{-4}\ kg$

Volume of gas, $V=1000\ cm^3=0.001\ m^3$

Pressure of gas at STP, $P=1.013\times 10^5\ Pa$

The rms velocity of gas molecules is given by :

$v_{rms}=\sqrt{ \dfrac{3PV}{m}}\\\\v_{rms}=\sqrt{\dfrac{3\times1.013\times10^{5}\times0.001}{1.77\times10^{-4}}}\\\\v_{rms}=1310.32\ m/s$

So, the rms velocity of the gas molecule is 1310.32 m/s.

Learn more,

RMS velocity of gas molecule

https://brainly.in/question/14726315