Question

A sample of 0.1g of water at 100degree celcius and normal pressure 1.013*100000 required 54 cal of heat energy to convert to steam at 100 degree celcius if the volume of the stream produced is 167.1cc. the change in internal energy of the sample is

Answer 1

Mass of water = 1 gm = .001 kg

Volume of water = mass/density = .001/1000=.000001 m³

= 1 cm³

Change in volume = 1650 -1 = 1649 cm³

dQ = m*L = 540 * 4.2 * 10^7 erg.

P = 1 atm = 76* 13.6 *9.8

dU = dQ - P* dV

= 22.68 * 10^9 - 1.67 * 10^9

= 21.01 * 10^9  erg

Answer 2

The solution is provided in the attachment.

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