Question

A sample of 100 gave a mean of 7.4 kg and standard deviation 1.2 kg. Find the 95% confidential limits for the population mean

Answer 1

Answer:

Deviation = 1.2 kg

Standard\ error = \frac{deviation}{\sqrt {100}}

= \frac{1.2}{\sqrt{100}}

= \frac{1.2}{10}

= 0.12 Kg

Confidence \ interval = Mean \pm 1.96\times standard \ error

= 100 \pm 1.96\times 0.12

= 99.7648 kg

95% confidence limit for the population mean is 99.7648 kg