A sample of 100 units is found to have 5 lb as mean.could it be regarded as a simple sample from a large population where mean is 5.64 and standard deviation is 1.5 lb.
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A sample of 100 units is found to have 5 lb as mean.could it be regarded as a simple sample from a large population where mean is 5.64 and standard deviation is 1.5 lb.
Explanation -
The standard normal statistics
z = (x’ - μ)/(σ/√n) = (x’ - μ)/(σ/10)
= {(x’ - μ)×10}/σ = {(5 - 5.6)x10}/1.5 ==>
|z| = 4 > 3 . Hence the deviation is highly significant, therefore the given sample can not be regarded as a simple sample from a large population with mean =5.6 and s.d. = 1.5 .
Standard deviation examples-
Consider the data set: 2, 1, 3, 2, 4. The mean and the sum of squares of deviations of the observations from the mean will be 2.4 and 5.2, respectively. Thus, the standard deviation will be √(5.2/5) = 1.01.
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