A sample of 16.0 g of a metal oxide ,MO, is reduced to 12.8 g of the metal,M.
What is the relative atomic mass , At, of M
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Answer:
Explanation:
It's 64g. And the metal is most probably copper(Cu).
The mole ratio for M and O in the compound MO is 1:1.
The mass of oxygen (O) in the 16g compound is 16.0 - 12.8 = 3.2g.
The RAM of O is 16g. The number of moles of O in the 3.2g is 3.2/16 = 0.2.
Since the M and O gave the same number of moles in the MO, that is their mole ratio is 1:1, then the number of moles of the M in the MO is also 0.2.
Therefore, if 0.2 mole if M weighs 12.8g, then 1 mole of M will weigh 1*12.8/0.2 = 64g/mole.
The grand/mole of an element is its relative atomic mass, RAM. Therefore, the RAM of M = 64. QED.
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