A sample of 2 g of CaCo3 contains 0.8 g of calcium 0.24 g of carbon and 0.96 g of oxygen.. calculate the percentage composition of compound by weight.
Answers
According to law of definite proportions, in a chemical substance, the elements are always present in definite proportions by mass. Given data: Percentage of Ca present in CaCO3 – 40% Percentage of C present in CaCO3 - 12% Percentage of O present in CaCO3 - 48% This means 100g of calcium carbonate contains 40g of Ca, 12g of C and 48g of O. Similarly, 2g of Calcium carbonate contains 40% calcium , 12% carbon and 48 % oxygen by mass. Let us find the masses of Ca, C and O present in 2g of CaCO3. Mass of Calcium present in 2g of CaCO3 = 40/100 X2 = 0.8g Mass of Carbon present in 2g of CaCO3 = 12/100 X 2 = 0.24g Mass of Oxygen present in 2g of CaCO3 = 48/12 X 2 = 0.96g.
Answer:
weight of sample =2g
mass of calcium= 0. 8g
mass of carbon = O.24g
mass of oxygen= 0.96g
% of calcium by weight = 0.8÷2 x 100
= 40%
% of carbon by weight = 0.24÷2x100
= 12%
% of oxygen by weight = 0.96÷2x100
= 48%
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