Chemistry, asked by Arushiii, 1 year ago

A sample of 2 g of CaCo3 contains 0.8 g of calcium 0.24 g of carbon and 0.96 g of oxygen.. calculate the percentage composition of compound by weight.

Answers

Answered by ApexPredator619
2

According to law of definite proportions, in a chemical substance, the elements are always present in definite proportions by mass. Given data: Percentage of Ca present in CaCO3 – 40% Percentage of C present in CaCO3 - 12% Percentage of O present in CaCO3 - 48% This means 100g of calcium carbonate contains 40g of Ca, 12g of C and 48g of O. Similarly, 2g of Calcium carbonate contains 40% calcium , 12% carbon and 48 % oxygen by mass. Let us find the masses of Ca, C and O present in 2g of CaCO3. Mass of Calcium present in 2g of CaCO3 = 40/100 X2 = 0.8g Mass of Carbon present in 2g of CaCO3 = 12/100 X 2 = 0.24g Mass of Oxygen present in 2g of CaCO3 = 48/12 X 2 = 0.96g.

Answered by aajagireesh12
1

Answer:

weight of sample =2g

mass of calcium= 0. 8g

mass of carbon = O.24g

mass of oxygen= 0.96g

% of calcium by weight = 0.8÷2 x 100

= 40%

% of carbon by weight = 0.24÷2x100

= 12%

% of oxygen by weight = 0.96÷2x100

= 48%

Hope it will help you...

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