Chemistry, asked by 20200500185, 4 days ago

A sample of 25.0cm³ of 0.500mol/dm³ aqueous ammonium nitrate is heated.Calculate the volume of nitrogen formed, measured at room temperature and pressure?​

Answers

Answered by jacobjeso77
0

Answer:

The amount in moles of a solute in a given volume of solution can be calculated if the concentration of the solution is known. The mass of solute can then be calculated.

Rearranging the equation for concentration below:

\[Concentration~in~mol/dm^{3}=\frac{amount~of~solute~in~mol}{volume~in~dm^{3}}\]

Gives:

Amount of solute in mol = concentration in mol/dm3 × volume in dm3

Example

Calculate the amount of sodium hydroxide, NaOH, in 25.0 cm3 of solution of concentration 0.1 mol/dm3.

Converting the volume from cm3 to dm3, 25.0 cm3 = 25.0 ÷ 1000 = 0.025 dm3.

Amount of NaOH in mol = concentration in mol/dm3 × volume in dm3

= 0.1 mol/dm3 × 0.025 dm3

= 0.0025 mol

Calculating masses from concentration and volume

If the amount in mol of a solute in a given volume of solution is known, its mass can also be calculated.

Question

For the example above, calculate the mass of NaOH in 25.0 cm3 of solution. (Mr = 40 g)

Explanation:

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